Tasks Details
easy
1.
Nesting
Determine whether a given string of parentheses (single type) is properly nested.
Task Score
100%
Correctness
100%
Performance
100%
A string S consisting of N characters is called properly nested if:
- S is empty;
- S has the form "(U)" where U is a properly nested string;
- S has the form "VW" where V and W are properly nested strings.
For example, string "(()(())())" is properly nested but string "())" isn't.
Write a function:
class Solution { public int solution(String S); }
that, given a string S consisting of N characters, returns 1 if string S is properly nested and 0 otherwise.
For example, given S = "(()(())())", the function should return 1 and given S = "())", the function should return 0, as explained above.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [0..1,000,000];
- string S is made only of the characters '(' and/or ')'.
Copyright 2009–2025 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
Solution
Programming language used Java 21
Time spent on task 23 minutes
Notes
not defined yet
Code: 15:17:31 UTC,
java,
verify,
result: Failed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Stack;
class Solution {
public int solution(String S) {
// write your code in Java SE 8
Stack<Character> st;
if(S == NULL)
return 1;
for(int i=0; i<S.length;i++){
if(S.charAt(i) == '(')
st.push('(');
else if(S.charAt(i) == ')' && !st.empty())
st.pop();
else if(S.charAt(i) == ')' && st.empty())
return 0;
}
if(st.empty())
return 1;
else
return 0;
}
}
Analysis
Compile error
Solution.java:15: error: illegal character: '\uff08' st.push?'('); ^ Solution.java:15: error: not a statement st.push?'('); ^ Solution.java:16: error: 'else' without 'if' else if(S.charAt(i) == ')' && !st.empty()) ^ 3 errors
Code: 15:22:17 UTC,
java,
verify,
result: Failed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Stack;
class Solution {
public int solution(String S) {
// write your code in Java SE 8
Stack<Character> st;
if(S == NULL)
return 1;
for(int i=0; i<S.length;i++){
if(S.charAt(i) == '(')
st.push(new Character('('));
else if(S.charAt(i) == ')' && !st.empty())
st.pop();
else if(S.charAt(i) == ')' && st.empty())
return 0;
}
if(st.empty())
return 1;
else
return 0;
}
}
Analysis
Compile error
Solution.java:15: error: illegal character: '\uff08' st.push?new Character('(')); ^ Solution.java:15: error: not a statement st.push?new Character('(')); ^ Solution.java:15: error: ';' expected st.push?new Character('(')); ^ Solution.java:16: error: 'else' without 'if' else if(S.charAt(i) == ')' && !st.empty()) ^ 4 errors
Code: 15:22:40 UTC,
java,
verify,
result: Failed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Stack;
class Solution {
public int solution(String S) {
// write your code in Java SE 8
Stack<Character> st;
if(S == NULL)
return 1;
for(int i=0; i<S.length;i++){
if(S.charAt(i) == '(')
st.push('(');
else if(S.charAt(i) == ')' && !st.empty())
st.pop();
else if(S.charAt(i) == ')' && st.empty())
return 0;
}
if(st.empty())
return 1;
else
return 0;
}
}
Analysis
Compile error
Solution.java:11: error: cannot find symbol if(S == NULL) ^ symbol: variable NULL location: class Solution Solution.java:13: error: cannot find symbol for(int i=0; i<S.length;i++){ ^ symbol: variable length location: variable S of type String 2 errors
Code: 15:23:44 UTC,
java,
verify,
result: Failed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Stack;
class Solution {
public int solution(String S) {
// write your code in Java SE 8
Stack<Character> st;
if(S == null)
return 1;
for(int i=0; i<S.length;i++){
if(S.charAt(i) == '(')
st.push('(');
else if(S.charAt(i) == ')' && !st.empty())
st.pop();
else if(S.charAt(i) == ')' && st.empty())
return 0;
}
if(st.empty())
return 1;
else
return 0;
}
}
Analysis
Compile error
Solution.java:13: error: cannot find symbol for(int i=0; i<S.length;i++){ ^ symbol: variable length location: variable S of type String 1 error
Code: 15:24:24 UTC,
java,
verify,
result: Failed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Stack;
class Solution {
public int solution(String S) {
// write your code in Java SE 8
Stack<Character> st;
if(S == null)
return 1;
for(int i=0; i<S.length();i++){
if(S.charAt(i) == '(')
st.push('(');
else if(S.charAt(i) == ')' && !st.empty())
st.pop();
else if(S.charAt(i) == ')' && st.empty())
return 0;
}
if(st.empty())
return 1;
else
return 0;
}
}
Analysis
Compile error
Solution.java:15: error: variable st might not have been initialized st.push('('); ^ Solution.java:16: error: variable st might not have been initialized else if(S.charAt(i) == ')' && !st.empty()) ^ Solution.java:18: error: variable st might not have been initialized else if(S.charAt(i) == ')' && st.empty()) ^ Solution.java:21: error: variable st might not have been initialized if(st.empty()) ^ 4 errors
Code: 15:24:53 UTC,
java,
verify,
result: Passed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Stack;
class Solution {
public int solution(String S) {
// write your code in Java SE 8
Stack<Character> st = new Stack<Character>();
if(S == null)
return 1;
for(int i=0; i<S.length();i++){
if(S.charAt(i) == '(')
st.push('(');
else if(S.charAt(i) == ')' && !st.empty())
st.pop();
else if(S.charAt(i) == ')' && st.empty())
return 0;
}
if(st.empty())
return 1;
else
return 0;
}
}
Analysis
Code: 15:25:10 UTC,
java,
verify,
result: Passed
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Stack;
class Solution {
public int solution(String S) {
// write your code in Java SE 8
Stack<Character> st = new Stack<Character>();
if(S == null)
return 1;
for(int i=0; i<S.length();i++){
if(S.charAt(i) == '(')
st.push('(');
else if(S.charAt(i) == ')' && !st.empty())
st.pop();
else if(S.charAt(i) == ')' && st.empty())
return 0;
}
if(st.empty())
return 1;
else
return 0;
}
}
Analysis
Code: 15:25:23 UTC,
java,
final,
score: 
100
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Stack;
class Solution {
public int solution(String S) {
// write your code in Java SE 8
Stack<Character> st = new Stack<Character>();
if(S == null)
return 1;
for(int i=0; i<S.length();i++){
if(S.charAt(i) == '(')
st.push('(');
else if(S.charAt(i) == ')' && !st.empty())
st.pop();
else if(S.charAt(i) == ')' && st.empty())
return 0;
}
if(st.empty())
return 1;
else
return 0;
}
}
Analysis summary
The solution obtained perfect score.
Analysis
Detected time complexity:
O(N)
expand all
Correctness tests
1.
0.034 s
OK
2.
0.044 s
OK
1.
0.070 s
OK
1.
0.411 s
OK
2.
0.097 s
OK
3.
0.051 s
OK
1.
0.057 s
OK
2.
0.067 s
OK
3.
0.068 s
OK
expand all
Performance tests
1.
0.138 s
OK
2.
0.163 s
OK
3.
0.061 s
OK
1.
0.572 s
OK
2.
0.084 s
OK
multiple_full_binary_trees
sequence of full trees of the form T=(TT), depths [1..10..1], with/without unmatched ')' at the end, length=49K+
sequence of full trees of the form T=(TT), depths [1..10..1], with/without unmatched ')' at the end, length=49K+
✔
OK
1.
0.377 s
OK
2.
0.360 s
OK
3.
0.036 s
OK
broad_tree_with_deep_paths
string of the form (TTT...T) of 300 T's, each T being '(((...)))' nested 200-fold, length=1 million
string of the form (TTT...T) of 300 T's, each T being '(((...)))' nested 200-fold, length=1 million
✔
OK
1.
1.629 s
OK
2.
0.036 s
OK